How do you solve #-6\leq 2x + 1\leq 21#?
1 Answer
Jun 8, 2017
Explanation:
#"isolate " 2x" by subtracting 1 from each interval"#
#-6-1<=2xcancel(+1)cancel(-1)<=21-1#
#rArr-7<=2x<=20#
#"divide all 3 intervals by 2"#
#rArr-7/2<=x<=10" is the solution"#