How do you simplify #(7+w)/(-7-w)#?

1 Answer
Jun 9, 2017

See a solution process below:

Explanation:

First, rewrite the denominator as:

#(7 + w)/(-1(7 + w)#

Now, cancel common terms in the numerator and denominator:

#color(red)(cancel(color(black)(7 + w)))/(-1color(red)(cancel(color(black)((7 + w))))) => 1/-1 = -1#

How, because we cannot divide by #0# in the original expression we need to restrict as:

Where #x != -7#