How do you find the real solutions of the polynomial #9x^2+5x^3=6x^4#?
1 Answer
Jun 10, 2017
Explanation:
#"rearrange the polynomial, equating to zero"#
#rArr6x^4-5x^3-9x^2=0#
#rArrx^2(6x^2-5x-9)=0larr" common factor"#
#"factor " 6x^2-5x-9" using the "color(blue)"quadratic formula"#
#"with " a=6,b=-5" and " c=-9#
#x=(5+-sqrt(25+216))/12=(5+-sqrt241)/12#
#rArrx~~1.71" or " x~~-0.88 " or x=0 #
