Question

A `5*L` volume of gas exerts a pressure of `124*kPa`. How should volume evolve if pressure is increased to `206*kPa`?

Answer 1

Well `P_1V_1=P_2V_2`....so `V_2=3.0*L`

Explanation:

Old `"Boyle's Law"` holds that for a given quantity gas, `Pprop1/V`, and thus `P=k/V`, where `k` is some (unspecified!) constant.

And if we solve for `k` under different conditions of pressure and volume (with temperature CONSTANT!), then.......

`V_2=(P_1xxV_1)/(P_2)=(5*Lxx124*kPa)/(206*kPa)=3.00*L`

Is this answer consistent with the parameters of the problem? Should volume DECREASE with INCREASED pressure?