Question #aee33

1 Answer
Stefan V.
Jun 10, 2017

#"46 g Y"#

Explanation:

The idea here is that compound #"XY"# will always contain elements #"X"# and #"Y"# in a

#"2 g X"/"4 g Y" = "1 g X"/"2 g Y"#

mass ratio. In other words, you will always have #"2 g"# of element #"Y"# for every #"1 g"# of element #"X"# present in the sample.

In your case, you know that the second sample contains #"23 g"# of element #"X"#, which means that it must also contain

#23 color(red)(cancel(color(black)("g X"))) * "2 g Y"/(1color(red)(cancel(color(black)("g X")))) = color(darkgreen)(ul(color(black)("46 g Y")))#

I'll leave the answer rounded to two sig figs.

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