How do you solve #(-3x)+11=2#?

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Answer 1 · 2017-06-11T00:44:53

See a solution process below:

Step 1) Subtract #color(red)(11)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#(-3x) + 11 - color(red)(11) = 2 - color(red)(11)#

#(-3x) + 0 = -9#

#-3x = -9#

Step 2) Divide each side of the equation by #color(red)(-3)# to solve for #x# while keeping the equation balanced:

#(-3x)/color(red)(-3) = (-9)/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))x)/cancel(color(red)(-3)) = 3#

#x = 3#