Question #1a2c9
2 Answers
Here's what I got.
Explanation:
I'll show you how to find the solubility of potassium chloride and lead(II) nitrate, and leave the solubility of potassium dichromate to you as practice.
The idea here is that the solubility graph of a given salt tells you the amount of salt that can be dissolved in a specific volume of solvent and at a specific temperature in order to get a saturated solution.
In your case, I am assuming that the solubility graph expresses the solubility of three salts in grams per liter of water,
So, start by finding the
You should find that it lies at a little over
Since you're trying to dissolve
#"500 g " - " 100 g" = "400 g"#
of undissolved salt. One significant figure will suffice here, so the answer will be
Do the same for lead(II) nitrate. Start at the
The way I see it, the value lies right between
Since the solution can hold a lot more lead(II) nitrate than you're trying to dissolve, i.e.
In other words, you will be left with
Here's what I get.
Explanation:
For each salt, we find 40 °C on the x-axis and go straight up until we hit the graph for that salt.
The solubility of
If we add 500 g of
The amount of solid
The solubility of
If we add 500 g of
The amount of solid
The solubility of
If we add 500 g of
The amount of solid