How do you simplify #(-9x^3yz^2)/(27x^4yz)#?

Question

1344 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-12T02:47:04

#(-9x^(3)yz^(2))/(27x^(4)yz)=color(blue)(-z/(3x)#

Simplify:

#(-9x^(3)yz^(2))/(27x^(4)yz)#

Simplify #-9/27# to #-1/3#.

#-(x^(3)yz^(2))/(3x^(4)yz)#

Apply quotient exponent rule: #a^m/a^n=a^(m-n)#.

#-(x^(3-4)y^(1-1)z^(2-1))/3#

Simplify.

#-(x^(-1)y^(0)z^(1))/3#

Apply zero exponent rule: #a^0=1#.

#-(x^(-1)1z^(1))/3#

Simplify.

#-(x^(-1)z^(1))/3#

Apply negative exponent rule: #a^(-m)=1/a^m#.

#-z/(3x)#