A model train, with a mass of #5 kg#, is moving on a circular track with a radius of #3 m#. If the train's rate of revolution changes from #1/3 Hz# to #3/8 Hz#, by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-06-12T13:25:16

The change in centripetal force is #=1.03N#

The centripetal force is

#F=mr omega^2#

mass is #m=5kg#

radius #r=3m#

#Delta omega=(3/8-1/3)*2pi=(1/12pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=5*3*(1/12pi)^2#

#=1.03N#