Question

How do you solve `2c+13=19`?

Answer 1

See a solution process below:

Explanation:

Step 1) Subtract `color(red)(13)` from each side of the equation to isolate the `c` term while keeping the equation balanced:

`2c + 13 - color(red)(13) = 19 - color(red)(13)`

`2c + 0 = 6`

`2c = 6`

Step 2) Divide each side of the equation by `color(red)(2)` to solve for `c` while keeping the equation balanced:

`(2c)/color(red)(2) = 6/color(red)(2)`

`(color(red)(cancel(color(black)(2)))c)/cancel(color(red)(2)) = 3`

`c = 3`

Answer 2

`c=3`

Explanation:

We need to move all terms that don't contain `c` to the right side and solve.

`2c + 13 = 19`

-subtract `13` from each side

`2c cancel(+13 - 13) =19 -13`

`2c=6`

-divide each side by `2`

`c=3`