Question

How do you divide `( x ^ { 2} + 8x - 33) \div ( x - 3)`?

Answer 1

`x+11`

Explanation:

Your question : `(x^2+8x-33)/(x-3)`

Try factoring the numerator :

`((x+11)(x-3))/((x-3))`

Then, you can cancel out the common term : `x-3`

`((x+11)cancel(x-3))/(cancel(x-3))`

`x+11`