Question

How do you solve `-10-5n^2=-330`?

Answer 1

See a solution process below:

Explanation:

First, add `color(red)(10)` to each side of the equation to isolate the `n` term while keeping the equation balanced:

`color(red)(10) - 10 - 5n^2 = color(red)(10) - 330`

`0 - 5n^2 = -320`

`-5n^2 = -320`

Next, divide each side of the equation by `color(red)(-5)` to isolate `x^2` while keeping the equation balanced:

`(-5n^2)/color(red)(-5) = (-320)/color(red)(-5)`

`(color(red)(cancel(color(black)(-5)))n^2)/cancel(color(red)(-5)) = 64`

`n^2 = 64`

Now, take the square root of each side of the equation to solve for `n` while keeping the equation balanced. Remember, the square root of a number produces a positive and negative result:

`sqrt(n^2) = +-sqrt(64)`

`n = +-8`

Answer 2

See below

Explanation:

`-10-5n^2=-330`

`320=5n^2`

`64=n^2`

`n=pm8`