How do you solve 2( 3x + 4) = 5( x - 5) + 12(3x+4)=5(x5)+1?

2 Answers
Jun 14, 2017

To solve this equation, you must isolate xx through PEMDAS.

Explanation:

First, distribute the 22 to (3x+4)(3x+4), giving you (6x+8)(6x+8) on the left side.

On the right side, distribute the 55 to the (x-5)(x5), giving you (5x-25) + 1(5x25)+1 on the right side.

You should now have

6x+8 = 5x-25+16x+8=5x25+1

Add the +1+1 to -2525, giving you -2424.

You should now have

6x+8 = 5x-246x+8=5x24

Subtract 5x5x from both sides to get xx on the same side of the equation. You should get

x+8 = -24x+8=24

Subtract 88 from both sides to isolate xx, leaving you with

x = -32x=32

Hope this helped!

Jun 14, 2017

color(blue)(x=-32x=32

Explanation:

2(3x+4)=5(x-5)+12(3x+4)=5(x5)+1

:.6x+8=5x-25+1

:.6x-5x=-25+1-8

:.x=-24-8

:.color(blue)(x=-32

Substitute color(blue)(x=-32

:.2(3(color(blue)(-32))+4)=5((color(blue)(-32))-5)+1

:.2(-96+4)=5(-37)+1

:.-192+8=-185+1

:.-184=-184