How do you evaluate #\frac { 5\times 10^ { - 3} } { 8\times 10^ { - 2} }#?

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Answer 1 · 2017-06-14T06:40:30

#(5xx10^(-3))/(8xx10^(-2))=6.25xx10^(-2)#

#(5xx10^(-3))/(8xx10^(-2))#

= #5/8xx10^(-3)/10^(-2)#

= #0.625xx10^((-3-(-2)))#

= #0.625xx10^((-3+2))#

= #0.625xx10^(-1)#

= #6.25/10xx10^(-1)#

= #6.25xx10^(-1-1)#

= #6.25xx10^(-2)#