Hot objects with temperatures of 10 million Kelvin give off most of their radiation in which part of the electromagnetic spectrum?

1 Answer
Jun 14, 2017

Well, this can be estimated with Wien's Displacement Law:

#lambda_(max) = (2.8977729 xx 10^(-3) "m"cdot"K")/T#,

assuming your hot object of interest is a blackbody (not at all related to a woman!), i.e. an opaque body that does not reflect any light.

#lambda_(max)# gives the peak wavelength of a blackbody's radiation curve as a function of surface temperature.

So, if we assume the surface temperature of the object is #10^7# #"K"#, then its maximum wavelength is approximately:

#color(blue)(lambda_(max)) ~~ (2.8977729 xx 10^(-3) "m"cdot"K")/(10^7 "K")#

#= 2.90 xx 10^(-10) "m"#

#=# #color(blue)("0.290 nm")#,

which is around the X-ray region, with wavelength range #0.01 - "10 nm"#.