How do you solve #2( 3x + 4) = 5( x - 5) + 1#?

2 Answers
Jun 14, 2017

To solve this equation, you must isolate #x# through PEMDAS.

Explanation:

First, distribute the #2# to #(3x+4)#, giving you #(6x+8)# on the left side.

On the right side, distribute the #5# to the #(x-5)#, giving you #(5x-25) + 1# on the right side.

You should now have

#6x+8 = 5x-25+1#

Add the #+1# to #-25#, giving you #-24#.

You should now have

#6x+8 = 5x-24#

Subtract #5x# from both sides to get #x# on the same side of the equation. You should get

#x+8 = -24#

Subtract #8# from both sides to isolate #x#, leaving you with

#x = -32#

Hope this helped!

Jun 14, 2017

#color(blue)(x=-32#

Explanation:

#2(3x+4)=5(x-5)+1#

#:.6x+8=5x-25+1#

#:.6x-5x=-25+1-8#

#:.x=-24-8#

#:.color(blue)(x=-32#

Substitute #color(blue)(x=-32#

#:.2(3(color(blue)(-32))+4)=5((color(blue)(-32))-5)+1#

#:.2(-96+4)=5(-37)+1#

#:.-192+8=-185+1#

#:.-184=-184#