Question

If the length of a `47 cm` spring increases to `57 cm` when a `8 kg` weight is hanging from it, what is the spring's constant?

Answer 1

The spring constant is `=784kgs^-2`

Explanation:

The force is `F=mg=8g N`

The extension is `x=0.57-0.47=0.1m`

The spring constant is

`k=F/e=(8g)/0.1=784kgs^-2`