How do you solve 4(y-3)=48?
2 Answers
Jun 15, 2017
Explanation:
First, divide both sides of the equation by
y-3=48/4=12
Add
y=15
Jun 15, 2017
Explanation:
"divide both sides of the equation by 4"
4/4(y-3)=48/4
rArry-3=12
"add 3 to both sides"
ycancel(-3)cancel(+3)=12+3
rArry=15
color(blue)"As a check"
4(15-3)=4xx12=48=" right side"
rArry=15" is the solution"