How do you graph #y=3(2.5)^x#?

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Answer 1 · 2017-06-16T02:08:17

See below

#y=3(2.5)^x#

#y# is the graph of #2.5^x# scaled by #3#

#lim_"x->-oo" y =0#

and

#lim_"x->+oo" y =+oo#

Since these limits approach their value very quickly about #x=0#, I would suggest plotting points in the domain #(-4, 0.5)# to prepare the graph.

Also note that #y=3# at #x=0# since #3*2.5^0 = 3*1 =3#

The graph of #y# is shown below.

graph{3(2.5)^x [-4.72, 5.14, -0.325, 4.61]}