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Answer 1 · 2017-06-16T22:03:12

#C_8H_8O_3#

Empirical Formula of Vanillin

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Answer 2 · 2017-06-16T22:06:05

#C_8H_8O_3#

AS with all these problems, we assume a #100*g# mass of unknown compound and work out the molar quantities of each element....

#"Moles of carbon"=(63.15*g)/(12.011*g*mol^-1)=5.26*mol#.

#"Moles of hydrogen"=(5.30*g)/(1.00794*g*mol^-1)=5.26*mol#.

#"Moles of oxygen"=(31.55*g)/(15.999*g*mol^-1)=1.97*mol#.

We divide thru by the smallest molar quantity to give a trial empirical formula of........

#C_(2.67)H_(2.67)O_()#, but if we multiply this by 3 we get..........#"whole numbers as required. "#

#......................C_8H_8O_3#