Question

Question #e1200

Answer 1

`x=0`

Explanation:

`"distributing the brackets gives"`

`1/2xcancel(-3/2)cancel(+3/2)-x=5x`

`rArr1/2x-x-5x=0`

`rArr-11/2x=0rArrx=0`

`color(blue)"As a check"`

`"left side "=1/2(-3)+3/2=0`

`"right side "=5xx0=0`

`rArrx=0" is the solution"`

Answer 2

`color(green)(x=0`

Explanation:

`1/2(x-3)+(3/2)-x=5x`

`:.0.5x-1.5+1.5-x=5x`

`:.0.5x-x-5x=1.5-1.5`

`:.0.5x-6x=0`

`:.-5.5x=0`

`:.x=0/-5.5`

`:.color(green)(x=0`

Substitute `x=0`

`:.1/2((color(green)0)-3)+(3/2)-(color(green)0)=5(0)`

`:.(0.5 xx 0)-1.5+1.5-0=0`

`:.0-1.5+1.5-0=0`

`:.color(green)(0=0`