Question

Given a 500 m sample of H`_2` at 2.00 atm pressure. What will be the volume when the pressure is changed to 720. torr?

Answer 1

Well, `P_1V_1=P_2V_2`........so `V_2=1055.6*mL`

Explanation:

`V_2=(P_1V_1)/P_2`

`=(2*atmxx500*mL)/((720*"Torr")/(760*"Torr"*"atm"^-1))=1055.6*mL`.