Question

What is `tan(arccos(sqrt2/2))`?

Answer 1

`tan(Arccos(sqrt2/2))=1`

Explanation:

We know that `cos(1/4pi) = sqrt2/2 therefore Arccos(sqrt2/2) =1/4pi`

`thereforetan(arccos (sqrt2/2)) = tan(1/4pi)=1`