How do you evaluate #(1+ 3- 9) ^ { 3} - ( - 2)#?

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Answer 1 · 2017-06-19T08:00:32

#-123#

#(1+3-9)^3#

#=(-5)^3#

#=-5xx-5xx-5#

#=-125#

#rArr(1+3-9)^3-(-2)larr -(-2)=+2#

#=-125+2#

#=-123#

Answer 2 · 2017-06-19T08:03:46

#-123#

Method- Simplify the numbers within the parenthesis, then expand and simplify further.

#(1+3-9)^3-(-2)#

#=(-5)^3+2#

#=(-5*-5*-5)+2#

#=(25*-5)+2#

#=-125+2#

#=-123#