How do you find the x and y intercept of #5x - 7y = 1#? Algebra Graphs of Linear Equations and Functions Intercepts by Substitution 1 Answer marfre Jun 20, 2017 #x#-intercept: #(1/5, 0); " "y#-intercept: #(0, -1/7)# Explanation: Given: #5x - 7y = 1# To find the #x#-intercept, set #y = 0# and solve for #x#: #5x - 7(0) = 1# #5x = 1# #(5x)/5 = 1/5# #x#-intercept: #(1/5, 0)# To find the #y#-intercept, set #x = 0# and solve for #y#: #5(0) - 7y = 1# #-7y = 1# #(-7y)/-7 = 1/(-7)# #y#-intercept: #(0, -1/7)# Answer link Related questions What is the x and y Intercepts? How many intercepts can a line have? How do you use substitution to find intercepts? How do you identify the intercepts on a linear graph? How do you use the x and y intercepts to graph a linear equation? How do you find the x and y intercept for #y=2x+3#? How do you find the x intercept for #y=2#? What is the y intercept for the #y=2# graph? What is the y intercept for #x=-1#? How do you find the intercepts of #x^2y-x^2+4y=0#? See all questions in Intercepts by Substitution Impact of this question 2951 views around the world You can reuse this answer Creative Commons License