How do you solve the system of equations #6+ y = 2x# and #- 3x - y = 1#?

1 Answer
Jun 20, 2017

#x=1 , y=-4#

Explanation:

Method: Rearrange the equations and solve by substitution.

#6+y=2x#

#y=2x-6# ---- Equation 1

#-3x-y=1# ----Equation 2

Substituting equation 1 into equation 2,

#-3x-(color(red)(2x-6))=1#

#-3x-2x+6=1#

#-5x=-5#

#x=1#

Substituting #x=1# into equation 1,

#y=color(red)2-6#

#y=-4#

Double check your working.