How do you solve the system of equations #6+ y = 2x# and #- 3x - y = 1#?

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Answer 1 · 2017-06-20T04:55:00

#x=1 , y=-4#

Method: Rearrange the equations and solve by substitution.

#6+y=2x#

#y=2x-6# ---- Equation 1

#-3x-y=1# ----Equation 2

Substituting equation 1 into equation 2,

#-3x-(color(red)(2x-6))=1#

#-3x-2x+6=1#

#-5x=-5#

#x=1#

Substituting #x=1# into equation 1,

#y=color(red)2-6#

#y=-4#

Double check your working.