Question

Please help How do I graph the polar equation `r^2=4sinθ` ?

Answer 1

`r=2sqrtsin(θ); 0<=theta<=pi`

Explanation:

Because the square of the radius cannot equal a negative number, we must add the following restriction:

`r^2=4sin(θ); 0<=theta<=pi`

This allows to take the square root of both sides of the equation without being concerned with the negative values:

`r=2sqrtsin(θ); 0<=theta<=pi`

Here is a graph of the equation: