How do you factor #18x^2-2#?

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Answer 1 · 2017-06-20T07:44:58

#2(3x+1)(3x-1)#

First look for common factors

#18x^2-2=2(9x^2-1)#

then see if the bracket can be factorised

we note difference of squares hence

#2(9x^2-1)=2(3x+1)(3x-1)#

Answer 2 · 2017-06-20T07:46:03

#= 2(3x+1)(3x-1)#

Always look for a common factor first. IN this case it is #2#

#18x^2 -2 = 2(9x^2-1)" "larr# difference of squares

#= 2(3x+1)(3x-1)#

Note that:

#x^2-y^2 = (x+y)(x-y)#