How do you solve #\sqrt { 5x + 56} - 6= 3x - 12#?

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Answer 1 · 2017-06-20T20:05:19

#x=-4/9, 5#

#sqrt(5x+56)−6=3x−12#

The first step is to isolate the radicand.

#sqrt(5x+56)=3x-6#

Next, square both sides of the equation to cancel out the radical.

#sqrt((5x+56)^2)=(3x-6)^2#
#5x+56=9x^2 -36x +36#

Move all the terms to one side so it can be factored.

#0=9x^2-41x-20#

Foil the side with all the terms.

#0=(9x+4)(x-5)#

Set each factor equal to 0.

#0=9x+4#
#0=x-5#

Solve each equation for x.

#x=-4/9, 5#

Now you have your answer! :)