How do you solve #|6x - 5| > 0#?

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Answer 1 · 2017-06-21T03:00:54

#x in RR, " "x ne 5/6#

Remember the rule that:

#|a|>b#

#a>b " " or " " a < -b#

In this case, we have that:

#|6x-5| > 0#

#6x-5 > 0 " " or " " 6x-5 < 0#

Hmm... this is just a fancy way of saying that 6x-5 can't be 0. So:

#6x-5 ne 0#

#6x ne 5#

#x ne 5/6#

Final Answer