Question

If `h(x) = x-7 and g(x) = x^2`, what is `(g*h)(5)`?

Answer 1

Because the domain of h and g is the set of real numbers their product can be defined.

Hence

`h(x)*g(x)=(h*g)(x)=(x-7)*x^2`

Hence

`(h*g)(5)=(5-7)*5^2=-50`