How do you solve the system of equations 2p + 3q = 1 and 4p - 5q = 13?

1 Answer
Jun 21, 2017

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Explanation:

Method - Use substitution to solve for p and q.

2p+3q = 1

2p=1-3q --- Let this be equation 1

4p-5q=13 --- Let this be equation 2

Substitute equation 1 into 2,

2(color(red)(1-3q)) -5q=13

2-6q-5q=13

-11q=11

q=-1

Substituting q=-1 into Equation 1,

2p=1-3(color(red)(-1))

2p = 4

p=2