How do you solve the system of equations #2p + 3q = 1# and #4p - 5q = 13#?

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Answer 1 · 2017-06-21T07:25:20

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Method - Use substitution to solve for p and q.

#2p+3q = 1#

#2p=1-3q# --- Let this be equation 1

#4p-5q=13# --- Let this be equation 2

Substitute equation 1 into 2,

#2(color(red)(1-3q)) -5q=13#

#2-6q-5q=13#

#-11q=11#

#q=-1#

Substituting #q=-1# into Equation 1,

#2p=1-3(color(red)(-1))#

#2p = 4#

#p=2#