What is #(- 6+ | - 3| ) \cdot ( 4- 3\cdot 2) \div ( | - 2| )#?

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Answer 1 · 2017-06-21T13:40:37

3

The absolute value of #-3# is #3#.

The absolute value of #-2# is #2#.

Let's rewrite the equation

#(-6+3)*(4-3*2)div(2)#

Let's solve the LHS bracket.

#-6+3=-3#

#-3*(4-3*2)div(2)#

Now, the middle bracket.

#4-3*2# ←　 You have to multiply first
#4-6#
#-2#

#-3*-2div(2)#
#6div2#
#3#