Question #253f8

1 Answer
Jun 21, 2017

#lambda=0.3590 m=3.590xx10^-1 m#

Explanation:

c = #lambda#v

c is the speed of light in meters/second, a constant #3.00xx10^-8#
#lambda# is wavelength of the electromagnetic wave in meters (what we want)
v is the frequency in 1/s or #s^-1#

Convert 835.6 MHz to Hz. There are #10^6# Hz in 1 MHz.
#835.6 cancel(MHz) xx (10^6Hz)/(1cancel(MHz))=8.356xx10^8Hz#

Plug what you know into the equation.

#3.00xx10^8m/s=lambda*8.356xx10^8s^-1#

#(3.00xx10^8m/cancel(s))/(8.356xx10^8cancel(s^-1))=lambda=0.3590=3.590xx10^-1 m#