Question

How do you divide `\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }`?

Answer 1

Here is the answer:`((8y^19)/(x^15))`

Explanation:

First of all, expand the exponents:`((4x^8y^5)/(8x^3y^3))/((x^24y^15)/(16x^4y^32))`

Next, switch the sign and find the reciprocal of the fraction:`((4x^8y^5)/(8x^3y^3))*((16x^4y^32)/(x^24y^15))`

Multiply:`((64x^12y^37)/(8x^27y^18))`

Cancel terms to get the final answer:`((8y^19)/(x^15))`

Hope this helps!