Question

Question #09add

Answer 1

`X = 32.1 g/m`

Explanation:

Set up a ratio and solve for X

`5.72 /10 = (4x)/ ( 4x + 6(O)`

5.72 = the amount of X in the compound

4x = the amount of X in the compound

so `5.72 = 4x`

10 = the total amount of the Compound

4x + 6(O) the total amount of the Compound

so `10 = 4X + 6(O)` The ratio is

`5.72/10 = (4X) / ( 4X + 6O)`

`6 xx 16 = 96` : `O = 16g/m`

`5.72/10 = (4x)/(4X + 96)` removing the denominators gives

`5.72(4x) + 5.72(96) = 40X` multiplying this out gives.

`22.88 X + 549. = 40X` subtract 22.88 X from both sides

`22.88 X - 22.88 X + 549 = 40X - 22.88X` This gives

`549 = 17.12 X` divide both sides by 17.12 gives

`32.1 g. = X`

Within the margin of error the grams / mole is approximately 32 grams/mole X is probably Sulfur