Question

How do you multiply `(6+ i \sqrt { 2} ) ( 4+ i \sqrt { 3} )`?

Answer 1

I tried this:

Explanation:

You need to remember that:
`i*i=i^2=(sqrt(-1))^2=-1`

So you can multiply as usual the two brackets:

`6*4+6*isqrt(3)+4*isqrt(2)+isqrt(2)*isqrt(3)=`

`=24+6isqrt(3)+4isqrt(2)-sqrt(6)=`

`=[24-sqrt(6)]+i[6sqrt(3)+4sqrt(2)]`

in the form `a+ib`