How do you solve #4( x + 4) \geq 3( x + 5) + x#?

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Answer 1 · 2017-06-24T02:11:06

#16>=15#, which is always true, therefore there are an infinite number of values for #x#.

Solve:

#4(x+4)>=3(x+5)+x#

Expand both sides.

#4x+16>=3x+15+x#

Simplify.

#4x+16>=4x+15#

Cancel the #4x# on both sides.

#color(red)cancel(color(black)(4x))+16>=color(red)cancel(color(black)(4x))+15#

#16>=15#

Because this inequality is always true, there are an infinite number of values for #x#