Question #d4f64

Question

912 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-25T00:43:42

See below.

The x-intercept is defined to be the point at which the line intersects the x-axis. You can calculate it by substituting #y=0# into the equation:

#y=1/4x+1#

#0=1/4x+1#

#-1=1/4x#

#(-1)(4)=(1/4)x(4)#

On the right-hand side of the equation the #4#'s cancel since one is in the numerator and the other is in the denominator.

#x=-4#

So the x-intercept is #(-4,0)#

The y-intercept is defined to be the point at which the line intersects the y-axis. You can calculate it by substituting #x=0# into the equation:

#y=1/4x+1#

#y=1#

The y-intercept is #(0,1)#

Here's what the graph looks like:

graph{1/4x+1 [-10, 10, -5, 5]}