Question

A `3.49*g` mass of a gas occupies a volume of `4.48*dm^3` under standard conditions, what is the molar mass of the gas?

Answer 1

`"Molar mass"=17.5*g*mol^-1`

Explanation:

Depending on your syllabus, at `"STP"` `1*mol` of Ideal Gas occupies `22.4*dm^3`, i.e. `22.4*dm^3*mol^-1`.......and note that `1*dm^3=1xx(10^-1*m)^3=1/1000*m^3=1*L`, cos' there are `1000*L` in a `"cubic metre"`.

And thus the `"molar mass"="mass"/"molar quantity"`

`=(3.49*g)/((4.48*dm^3)/(22.4*dm^3*mol^-1))=17.5*g*mol^-1`.......