How do you solve #\frac { 3x } { 2} - 3= \frac { x } { 3} + \frac { 1} { 2}#?

1 Answer
Jun 29, 2017

#x=23/9# OR #x=2.bar5#

Explanation:

You first want to get the terms that have an #x# onto one side, and the terms without one onto the other. This can be done by subtracting #-x/3# on both sides, and by adding #3# onto both sides.
Then you get
#(3x)/2-x/3=3+1/2#

Find common denominators for the left hand side (which is 6) and change the right hand side to a mixed number:
#(9x)/6-2/6=7/2#

The left hand side can now be written as
#(9x-2)/6=7/2#

Multiply both sides by 6:
#9x-2=42/2#

Simplify the right hand side:
#9x-2=21#

Add 2 to both sides:
#9x=23#

Divide both sides by 9:
#x=23/9#