How do you multiply #(3+ 4c ) ( 8- 5c )#?

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Answer 1 · 2017-06-29T12:48:05

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3) + color(red)(4c))(color(blue)(8) - color(blue)(5c))# becomes:

#(color(red)(3) xx color(blue)(8)) - (color(red)(3) xx color(blue)(5c)) + (color(red)(4c) xx color(blue)(8)) - (color(red)(4c) xx color(blue)(5c))#

#24 - 15c + 32c - 20c^2#

We can now combine like terms:

#24 + (-15 + 32)c - 20c^2#

#24 + 17c - 20c^2#

Or, in standard polynomial form:

#-20c^2 + 17c + 24#