Question

How do you evaluate `15- 2+ 1\times 3+ 4`?

Answer 1

The answer is 20 and see below for the procedure!

Explanation:

So for this equation, since it is the Order of the Operations, I will be using PEMDAS:

P - Parentheses
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction

Note: For multiplication and division, do whichever one that comes first in the equation and same for addition and subtraction. :)
Now, let's start working it out!

Procedure:
Parentheses:
None

Exponents:
None

Multiplication:
`15−2+ **1×3** +4`
I made the problem bold.

`1times3=**3**`

Now the equation will be, `15−2+3+4`!

Division:
None

Now lets move on to Addition! But, wait a second, Subtraction is before Addition in the equation so we have to do Subtraction first now! Lets solve the subtraction problem in the equation, so let's solve it now!

Subtraction:
`**15-2**+3+4`
I made the problem bold.

`15-2=**13**`

The equation now is `13+3+4`!

Addition:
#**13+3+4** #13+3=16# #16+4=20#

So our final answer is `20`!
My source is my mind!