Question #65db0

1 Answer
Pablocito · Truong-Son N.
Jun 29, 2017

It is the time #t_"1/2"# necessary for a radioactive mass to lose half its mass.

Explanation:

The decay is an exponential function

#M_(t) = M_(0) [ 1/2 ]^( t // t_"1/2" )#

#M_(0) = "initial mass at"# #t=0#

Note if #t = t_"1/2"# then #M_(t_"1/2") = 1/2# #"initial mass"#

Related questions
Impact of this question
698 views around the world
You can reuse this answer
Creative Commons License