A certain red light has a wavelength of 680 nm. What is the frequency of the light?

1 Answer
Jun 30, 2017

f = 4.4 xx 10^14f=4.4×1014 "s"^-1s1

Explanation:

We're asked to convert a given wavelength of a wave to its frequency.

We can use the equation

lambdaf = cλf=c

where

  • lambdaλ (the lowercase Greek letter lambda) is the wavelength of the wave, in meters

  • ff is the frequency of the wave, in inverse seconds ("s"s) or hertz ("Hz"Hz)

  • cc is the speed of light in vacuum, precisely 299,792,458299,792,458 "m/s"m/s

Since our wavelength must be in units of "m"m, we'll convert from nanometers to meters, knowing that 11 "m"m = 10^9=109 "nm"nm:

680cancel("nm")((1color(white)(l)"m")/(10^9cancel("nm"))) = color(red)(6.80 xx 10^-7 color(red)("m"

Plugging in known values to the equation and solving for f, we have

f = c/lambda

f = (299792458(cancel("m")/"s"))/(6.80xx10^-7cancel("m")) = color(blue)(4.4 xx 10^14 color(blue)("s"^-1) = color(blue)(4.4 xx 10^14 color(blue)("Hz"

rounded to 2 significant figures.