How do you solve the system of equations #y=3x-7# and #2x+3y=12# graphically?

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Answer 1 · 2017-07-01T01:15:05

#(3,2)#

#y=3x-7#

You have to plot -7 as a point on the y-axis. Then you go up three and over one for your slope in order to draw your line:

graph{y=-7+3x [-10, 10, -5, 5]}

#2x+3y=12#

This can be rewritten as #y=4+2/3x#. Then you plot 4 as a point on the y-axis and go up 4 and over 1 as well.

graph{y=-2/3x+4}

Together they look like this:

graph{(y-3x+7)(y+2/3x-4)=0}

For a solution of #(3,2)#