How do you solve the system of equations #y=3x-7# and #2x+3y=12# graphically?
1 Answer
Jul 1, 2017
Explanation:
#y=3x-7#
You have to plot -7 as a point on the y-axis. Then you go up three and over one for your slope in order to draw your line:
graph{y=-7+3x [-10, 10, -5, 5]}
#2x+3y=12#
This can be rewritten as
graph{y=-2/3x+4}
Together they look like this:
graph{(y-3x+7)(y+2/3x-4)=0}
For a solution of