Question

How do you normalize `(3i – 4j + 4k)`?

Answer 1

The answer is `=3/sqrt41i-4/sqrt41j+4/sqrt41k`

Explanation:

Let `vecv=<3,-4,4>`

The magnitude of `vecv` is

`||vecv||=||<3,-4,4>||=sqrt(3^2+(-4)^2+4^2)=sqrt(9+16+16)=sqrt41`

Therefore, the normalized vector is

`hatv=vecv/(||vecv||)=1/sqrt41*<3,-4,4>`