How do you solve $3 y - 4 \leq - 10$ $3y - 4\leq - 10$ ?

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Answer 1 · 2017-07-01T15:49:38

See a solution process below:

First, add $4$ $color(red)(4)$ to each side of the inequality to isolate the $y$ $y$ term while keeping the inequality balanced:

$3 y - 4 + 4 \leq - 10 + 4$ $3y - 4 + color(red)(4) <= -10 + color(red)(4)$

$3 y - 0 \leq - 6$ $3y - 0 <= -6$

$3 y \leq - 6$ $3y <= -6$

Now, divide each side of the inequality by $3$ $color(red)(3)$ to solve for $y$ $y$ while keeping the inequality balanced:

$\frac{3 y}{3} \leq - \frac{6}{3}$ $(3y)/color(red)(3) <= -6/color(red)(3)$

$(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) <= -2$

$y <= -2$

How do you solve 3y - 4\leq - 103y−4≤−103y - 4\leq - 10?