How do you graph #y=3x+7# using intercepts?
1 Answer
Jul 1, 2017
Explanation:
#"to find the intercepts"#
#• " let x = 0, in equation for y-intercept"#
#• " let y = 0, in equation for x-intercept"#
#x=0toy=0+7toy=7larrcolor(red)" y-intercept"#
#y=0to3x+7=0tox=-7/3larrcolor(red)" x-intercept"#
#"plot the points " (0,7),(-7/3,0)" and draw a straight line"#
#"through them"#
graph{3x+7 [-20, 20, -10, 10]}
