Find the largest integer such that 8 more than six times the integer is less than -42.?

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Answer 1 · 2017-07-01T20:09:21

The largest integer that satisfies this is #-9#.

Translating this into an equation would be:

"Find the largest integer #x# such that #6x+8<-42#."

Simplifying the inequality:

#6x+8<-42#

#6x<-50#

#x<-\frac{50}{6}#

#x<-8.333#

So, the largest integer less than #-8.333# would be #-9#.